(2k-3)(2k^2-9k-5)=0

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Solution for (2k-3)(2k^2-9k-5)=0 equation: 


Simplifying
(2k + -3)(2k2 + -9k + -5) = 0

Reorder the terms:
(-3 + 2k)(2k2 + -9k + -5) = 0

Reorder the terms:
(-3 + 2k)(-5 + -9k + 2k2) = 0

Multiply (-3 + 2k) * (-5 + -9k + 2k2)
(-3(-5 + -9k + 2k2) + 2k * (-5 + -9k + 2k2)) = 0
((-5 * -3 + -9k * -3 + 2k2 * -3) + 2k * (-5 + -9k + 2k2)) = 0
((15 + 27k + -6k2) + 2k * (-5 + -9k + 2k2)) = 0
(15 + 27k + -6k2 + (-5 * 2k + -9k * 2k + 2k2 * 2k)) = 0
(15 + 27k + -6k2 + (-10k + -18k2 + 4k3)) = 0

Reorder the terms:
(15 + 27k + -10k + -6k2 + -18k2 + 4k3) = 0

Combine like terms: 27k + -10k = 17k
(15 + 17k + -6k2 + -18k2 + 4k3) = 0

Combine like terms: -6k2 + -18k2 = -24k2
(15 + 17k + -24k2 + 4k3) = 0

Solving
15 + 17k + -24k2 + 4k3 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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